AR 3-1-4 / Tournament Tie Breaker

1. A tournament with 10 teams, all play once against each other. 5 teams (A, B, C, D, E) have the same percentage after their 9 games, so to make a ranking you look at the percentage just for their games.
   1. A, B and C still have the same percentage, D and E have the same but lower percentage. So the system will split them into the first group of 3 and second group of 2 which will be further looked on separately.

2a. A has a net point differential of +6, B and C have -2 for their games just in the group of 3.

So A is first in the tie breaker. The remaining 2 will be further looked on separately.

3a. B and C have played a tie, so there is no decision on points scored.

4a. B has an overall net point differential of +11, C has -5. So B is second, C is third in the tie breaker.

2b. D and E have played a tie, so there is no decision on net point differential for their games just in the group of 2.

3b. D and E have played a tie, so there is no decision on points scored just in the group of 2. 4b. D and E have the same overall net point differential.

5b. D has more points scored overall than E. So D is fourth, E is fifth in the tie breaker.